Dhananjay Kumar

Using Lambda expression in FindAll()

I got a critical comment from @amazedsaint. You can read his blog http://amazedsaint.blogspot.com/

If you read my previous post http://dhananjaykumar.net/2010/10/01/findall-finding-multiple-items-in-c-list/ ,

I am using a method GreaterThanHun As predicate to pass as parameter to FindAll()

Instead of that we can use

1. Anonymous method

2. Lambda expression

So, I am going to show you here how we could use Lambda expression

clip_image002

So here we are just writing a lambda instead of calling a function.

Program.cs

using System;

using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication24
{
    class Program
    {
        static void Main(string[] args)
        {
            List<int> lst = new List<int>();
            lst.Add(20);
            lst.Add(300);
            lst.Add(400);
            lst.Add(9);
            lst.Add(19);
            lst.Add(789);
            lst.Add(45);
            List<int> lstgrthund = lst.FindAll(a=>a>100? true:false);
            foreach (var r in lstgrthund)
            {
                Console.WriteLine(r);
            }
            Console.ReadKey(true);
        }

Output

clip_image004

Dhananjay Kumar | Angular Teacher | Angular Consultant | ng-India

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3 responses to “Using Lambda expression in FindAll()”

  1. Anonymous

    i think
    List lstgrthund = lst.FindAll(a>100);
    would have done the trick… since its a predicate

  2. Dhananjay Kumar

    Yes my purpose was just to explain in rather more detail to beginner

  3. Patrick

    Dhananjay… i didn’t want to register on dotnet spark, but I wanted to send you a comment on your article “Step by Step tutorial of REST Enabled Service in WCF”

    Nicely done and relevant. There was, however a small bug in your example code. You are missing a bracket after the using in the following code:

    public static string AddWithoutParameter()
    {
    using (HttpResponseMessage response = new HttpClient().Get(uri))

    int res = response.Content.ReadAsDataContract();
    return res.ToString();
    }
    }

    Thanks again for the nice article!
    Patrick

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