Dhananjay Kumar

Objective

This article will give a very simple and basic explanation of , how to fetch an image using WCF REST service.

Step 1

Create a WCF application. To create a new application File -> New -> Web-> WCF Service Application.Remove all the default code created by WCF. Remove code from IService 1 interface and Service1 class. Remove the code from Web.Config also. Open Web.Config and remove System.Servicemodel codes.

Step 2

Right click on Service1.svc select View markup and add below code

<%@
ServiceHost
Language=”C#”
Debug=”true”
Service=”FetchingImageinBrowser.Service1″
CodeBehind=”Service1.svc.cs”
Factory=”System.ServiceModel.Activation.WebServiceHostFactory”
%>

Step 3

Create contract. Operation contract will return Stream. Stream is in the namespace System.IO. By putting WebGet attribute make operation contract

IService1.cs

1 using System;

2 using System.Collections.Generic;

3 using System.Linq;

4 using System.Runtime.Serialization;

5 using System.ServiceModel;

6 using System.ServiceModel.Web;

7 using System.Text;

8 using System.IO;

9 namespace FetchingImageinBrowser

10 {

11 [ServiceContract]

12 public interface IService1

13 {

14

15 [OperationContract]

16 [WebGet(UriTemplate = “GetImage”, RequestFormat = WebMessageFormat.Xml, ResponseFormat = WebMessageFormat.Xml, BodyStyle = WebMessageBodyStyle.Bare)]

17 Stream GetImage();

18

19 }

20 }

21

22

23

Implement service. In service class write the below code. Using FileStream open and read the image. Then set outgoing response as image/jpeg using WebOperationContext class.

Service1.svc.cs

1 using System;

2 using System.Collections.Generic;

3 using System.Linq;

4 using System.Runtime.Serialization;

5 using System.ServiceModel;

6 using System.ServiceModel.Web;

7 using System.Text;

8 using System.IO;

9

10 namespace FetchingImageinBrowser

11 {

12 public class Service1 : IService1

13 {

14 public Stream GetImage()

15 {

16 FileStream fs = File.OpenRead(@”D:\a.jpg”);

17 WebOperationContext.Current.OutgoingResponse.ContentType = “image/jpeg”;

18 return fs;

19 }

20

21 }

22 }

23

Step 4

Press F5 to run the application. Append GetImage/ in URL to get the output.